前言
《诈金花》又叫三张牌,是在全国广泛流传的一种民间多人纸牌游戏。比如JJ比赛中的诈金花(赢三张),具有独特的比牌规则。游戏过程中需要考验玩家的胆略和智慧。--《百度百科》 前几天在交流群里边,有个叫【^-^】的粉丝分享了一道扑克牌诈金花的题目,要求用Python实现,题目如下:
自己写一个程序,实现发牌、比大小判断输赢。
游戏规则:
一付扑克牌,去掉大小王,每个玩家发3张牌,最后比大小,看谁赢。
有以下几种牌:
豹子:三张一样的牌,如3张6.
顺金:又称同花顺,即3张同样花色的顺子, 如红桃 5、6、7
顺子:又称拖拉机,花色不同,但是顺子,如红桃5、方片6、黑桃7,组成的顺子
对子:2张牌一样
单张:单张最大的是A
这几种牌的大小顺序为, 豹子>顺金>顺子>对子>单张
一、思路
针对这个问题,首先需要构造一副扑克牌,根据扑克牌的属性特征,进行不断的拆解,然后构造玩家用户,这里经常会用到字典和列表来存储信息,屡试不爽。
二、解决方案
针对该问题,粉丝【^-^】给出了解决方法,直接上代码如下:
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# -*- coding: utf-8 -*- import random puke = [] # 存储扑克牌 num_list = [ '2' , '3' , '4' , '5' , '6' , '7' , '8' , '9' , '10' , 'J' , 'Q' , 'K' , 'A' ] hua_list = [ '梅花' , '红桃' , '黑桃' , '方块' ] sort_dic = { '2' : 0 , '3' : 1 , '4' : 2 , '5' : 3 , '6' : 4 , '7' : 5 , '8' : 6 , '9' : 7 , '10' : 8 , 'J' : 9 , 'Q' : 10 , 'K' : 11 , 'A' : 12 , '对子' : 15 , '顺子' : 30 , '顺金' : 60 , '豹子' : 100 } count_new_list = [] # 存储玩家分数和排序后排名 count_dic = {} # 存储玩家分数 # 准备52张扑克 for hua in hua_list: for num in num_list: a = hua + num puke.append(a) player_dic = { '玩家1' : [], '玩家2' : [], '玩家3' : [], '玩家4' : [], '玩家5' : []} # 随机给五个玩家发牌 # print(len(puke)) for key, value in player_dic.items(): for i in range ( 3 ): plate = random.sample(puke, 3 ) player_dic[key] = plate for i in plate: puke.remove(i) print (player_dic) # 获取玩家的牌型 def paixing(list1): num = [] huase = [] for i in list1: a = i[ 2 :] b = i[: 2 ] num.append(a) huase.append(b) return num, huase # sort_dic = {'2': 0, '3': 1, '4': 2, '5': 3, '6': 4} # 对数字的牌型进行排序 def sort(num): new_num = [] sort_list2 = [] list1 = [] for i in num: new_num.append(sort_dic[i]) new_num = sorted (new_num) # 排序后是[2, 4, 7] for new in new_num: sort_list2.append([k for k, v in sort_dic.items() if v = = new]) for m in sort_list2: for n in m: list1.append(n) return list1 # 对玩家的牌形统计分数 def count(num, huase): a = 0 base_count = sort_dic[num[ 0 ]] + sort_dic[num[ 1 ]] + sort_dic[num[ 2 ]] if num[ 0 ] = = num[ 1 ] and num[ 1 ] = = num[ 2 ]: paixing = '豹子' a = base_count + sort_dic[paixing] elif (sort_dic[num[ 0 ]] + 1 = = sort_dic[num[ 1 ]] and sort_dic[num[ 2 ]] - 1 = = sort_dic[num[ 1 ]]) and (huase[ 0 ] = = huase[ 1 ] and huase[ 1 ] = = huase[ 2 ]): paixing = '顺金' a = base_count + sort_dic[paixing] elif (sort_dic[num[ 0 ]] + 1 = = sort_dic[num[ 1 ]]) and (sort_dic[num[ 2 ]] - 1 = = sort_dic[num[ 1 ]]) and ( huase[ 0 ] ! = huase[ 1 ] or huase[ 1 ] ! = huase[ 2 ]): paixing = '顺子' a = base_count + sort_dic[paixing] elif (num[ 0 ] = = num[ 1 ] and num[ 1 ] ! = num[ 2 ]) or (num[ 1 ] = = num[ 2 ] and num[ 0 ] ! = num[ 1 ]) or ( num[ 0 ] = = num[ 2 ] and num[ 1 ] ! = num[ 0 ]): paixing = '对子' a = base_count + sort_dic[paixing] else : a = base_count return a # 对存储玩家分数的字典进行排序 def compare(count_dic): d = list ( zip (count_dic.values(), count_dic.keys())) return sorted (d, reverse = True ) for key, value in player_dic.items(): num, huase = paixing(value) num = sort(num) count1 = count(num, huase) count_dic[key] = count1 print (key + "的牌为:" + str (value)) count_new_list = compare(count_dic) # print(count_new_list) print ( '最终排名:' + "\t" + count_new_list[ 0 ][ 1 ] + "第一名" + "\t" + count_new_list[ 1 ][ 1 ] + "第二名" + "\t" + count_new_list[ 2 ][ 1 ] + "第三名" + "\t" + count_new_list[ 3 ][ 1 ] + "第四名" + "\t" + count_new_list[ 4 ][ 1 ] + "第五名" ) |
代码看上去确实挺多的,超过了100行,需要花点时间去读,不过涉及的知识点并不复杂,基本上有点Python基础,也可以理解。代码运行之后,可以看到效果如下:
不过后来我在读取这份代码的时候,发现中间有个地方写的着实有些冗余,稍微修改下,代码方面简洁一些,一些函数和变量命名加了一些对应的现实意义的单词,可读性强了一丢丢,代码如下:
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# -*- coding: utf-8 -*- import random puke = [] # 存储扑克牌 num_list = [ '2' , '3' , '4' , '5' , '6' , '7' , '8' , '9' , '10' , 'J' , 'Q' , 'K' , 'A' ] hua_list = [ '梅花' , '红桃' , '黑桃' , '方块' ] sort_dic = { '2' : 0 , '3' : 1 , '4' : 2 , '5' : 3 , '6' : 4 , '7' : 5 , '8' : 6 , '9' : 7 , '10' : 8 , 'J' : 9 , 'Q' : 10 , 'K' : 11 , 'A' : 12 , '对子' : 15 , '顺子' : 30 , '顺金' : 60 , '豹子' : 100 } count_new_list = [] # 存储玩家分数和排序后排名 count_dic = {} # 存储玩家分数 # 准备52张扑克 for hua in hua_list: for num in num_list: a = hua + num puke.append(a) player_dic = { '玩家1' : [], '玩家2' : [], '玩家3' : [], '玩家4' : [], '玩家5' : []} # 随机给五个玩家发牌 print ( len (puke)) for key, value in player_dic.items(): for i in range ( 3 ): plate = random.sample(puke, 3 ) player_dic[key] = plate for i in plate: puke.remove(i) print (player_dic) # 获取玩家的牌型 def paixing(list1): num = [] huase = [] for data in list1: huase_type = data[: 2 ] pai_number = data[ 2 :] num.append(pai_number) huase.append(huase_type) return num, huase # 对玩家的牌形统计分数 def get_score(num, huase): base_count = sort_dic[num[ 0 ]] + sort_dic[num[ 1 ]] + sort_dic[num[ 2 ]] if num[ 0 ] = = num[ 1 ] and num[ 1 ] = = num[ 2 ]: paixing = '豹子' score = base_count + sort_dic[paixing] elif (sort_dic[num[ 0 ]] + 1 = = sort_dic[num[ 1 ]] and sort_dic[num[ 2 ]] - 1 = = sort_dic[num[ 1 ]]) and (huase[ 0 ] = = huase[ 1 ] and huase[ 1 ] = = huase[ 2 ]): paixing = '顺金' score = base_count + sort_dic[paixing] elif (sort_dic[num[ 0 ]] + 1 = = sort_dic[num[ 1 ]]) and (sort_dic[num[ 2 ]] - 1 = = sort_dic[num[ 1 ]]) and ( huase[ 0 ] ! = huase[ 1 ] or huase[ 1 ] ! = huase[ 2 ]): paixing = '顺子' score = base_count + sort_dic[paixing] elif (num[ 0 ] = = num[ 1 ] and num[ 1 ] ! = num[ 2 ]) or (num[ 1 ] = = num[ 2 ] and num[ 0 ] ! = num[ 1 ]) or ( num[ 0 ] = = num[ 2 ] and num[ 1 ] ! = num[ 0 ]): paixing = '对子' score = base_count + sort_dic[paixing] else : score = base_count return score if __name__ = = '__main__' : for key, value in player_dic.items(): num, huase = paixing(value) # 对数字的牌型进行排序 num = sorted (num) score = get_score(num, huase) count_dic[key] = score print (key + "的牌为:" + str (value)) # 对存储玩家分数的字典进行排序 count_new_list = sorted ( zip (count_dic.values(), count_dic.keys()), reverse = True ) print ( "最终排名:" ) for i in range ( len (count_new_list)): print (count_new_list[i][ 1 ] + '\t' , end = '') |
三、总结
我是Python进阶者。本文实际生活中的诈金花游戏,基于Python编程,使用Python基础知识中的列表、字典、函数等,实现了在线诈金花的过程。
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原文链接:https://developer.51cto.com/article/702708.html